1215524331041 has 2 divisors, whose sum is σ = 1215524331042. Its totient is φ = 1215524331040.

The previous prime is 1215524331013. The next prime is 1215524331137. The reversal of 1215524331041 is 1401334255121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1183221817600 + 32302513441 = 1087760^2 + 179729^2 .

It is a cyclic number.

It is not a de Polignac number, because 1215524331041 - 2¹⁸ = 1215524068897 is a prime.

It is a super-2 number, since 2×1215524331041² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1215524330989 and 1215524331007.

It is not a weakly prime, because it can be changed into another prime (1215524331001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607762165520 + 607762165521.

It is an arithmetic number, because the mean of its divisors is an integer number (607762165521).

Almost surely, 2^{1215524331041} is an apocalyptic number.

It is an amenable number.

1215524331041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1215524331041 is an equidigital number, since it uses as much as digits as its factorization.

1215524331041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 1215524331041 its reverse (1401334255121), we get a palindrome (2616858586162).

The spelling of 1215524331041 in words is "one trillion, two hundred fifteen billion, five hundred twenty-four million, three hundred thirty-one thousand, forty-one".