Base | Representation |
---|---|
bin | 1011000011110011101101… |
… | …0000101111111000000111 |
3 | 1121001111012120002212211021 |
4 | 2300330323100233320013 |
5 | 3043212233421124002 |
6 | 41510125345252011 |
7 | 2363351202126001 |
oct | 260747320577007 |
9 | 47044176085737 |
10 | 12160046661127 |
11 | 3969057368182 |
12 | 1444847034007 |
13 | 6a28c2515c31 |
14 | 30079979b371 |
15 | 16149da28737 |
hex | b0f3b42fe07 |
12160046661127 has 2 divisors, whose sum is σ = 12160046661128. Its totient is φ = 12160046661126.
The previous prime is 12160046661031. The next prime is 12160046661151. The reversal of 12160046661127 is 72116664006121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12160046661127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12160046661187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6080023330563 + 6080023330564.
It is an arithmetic number, because the mean of its divisors is an integer number (6080023330564).
Almost surely, 212160046661127 is an apocalyptic number.
12160046661127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12160046661127 is an equidigital number, since it uses as much as digits as its factorization.
12160046661127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 43.
The spelling of 12160046661127 in words is "twelve trillion, one hundred sixty billion, forty-six million, six hundred sixty-one thousand, one hundred twenty-seven".
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