Base | Representation |
---|---|
bin | 1011000011111111000110… |
… | …1110111110110101110011 |
3 | 1121001210002220122001012212 |
4 | 2300333301232332311303 |
5 | 3043240021124240201 |
6 | 41511353225242335 |
7 | 2363520104330663 |
oct | 260776156766563 |
9 | 47053086561185 |
10 | 12163108040051 |
11 | 396a388440501 |
12 | 14453603333ab |
13 | 6a2c8c83ac57 |
14 | 3009aa1c01a3 |
15 | 1615cc693abb |
hex | b0ff1bbed73 |
12163108040051 has 2 divisors, whose sum is σ = 12163108040052. Its totient is φ = 12163108040050.
The previous prime is 12163108040023. The next prime is 12163108040077. The reversal of 12163108040051 is 15004080136121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12163108040051 is a prime.
It is not a weakly prime, because it can be changed into another prime (12163108045051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6081554020025 + 6081554020026.
It is an arithmetic number, because the mean of its divisors is an integer number (6081554020026).
Almost surely, 212163108040051 is an apocalyptic number.
12163108040051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12163108040051 is an equidigital number, since it uses as much as digits as its factorization.
12163108040051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 32.
Adding to 12163108040051 its reverse (15004080136121), we get a palindrome (27167188176172).
The spelling of 12163108040051 in words is "twelve trillion, one hundred sixty-three billion, one hundred eight million, forty thousand, fifty-one".
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