Base | Representation |
---|---|
bin | 10110101010011000… |
… | …00110110011011101 |
3 | 1011101220201010022011 |
4 | 23111030012303131 |
5 | 144404130431242 |
6 | 5331141351221 |
7 | 610333601644 |
oct | 132514066335 |
9 | 34356633264 |
10 | 12166655197 |
11 | 518383a144 |
12 | 2436708511 |
13 | 11bb845578 |
14 | 835c0035b |
15 | 4b31ded17 |
hex | 2d5306cdd |
12166655197 has 2 divisors, whose sum is σ = 12166655198. Its totient is φ = 12166655196.
The previous prime is 12166655113. The next prime is 12166655209. The reversal of 12166655197 is 79155666121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11905864996 + 260790201 = 109114^2 + 16149^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12166655197 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12166655197.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12166653197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6083327598 + 6083327599.
It is an arithmetic number, because the mean of its divisors is an integer number (6083327599).
Almost surely, 212166655197 is an apocalyptic number.
It is an amenable number.
12166655197 is a deficient number, since it is larger than the sum of its proper divisors (1).
12166655197 is an equidigital number, since it uses as much as digits as its factorization.
12166655197 is an evil number, because the sum of its binary digits is even.
The product of its digits is 680400, while the sum is 49.
The spelling of 12166655197 in words is "twelve billion, one hundred sixty-six million, six hundred fifty-five thousand, one hundred ninety-seven".
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