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12167540000017 is a prime number
BaseRepresentation
bin1011000100001111100111…
…1001100100010100010001
31121002012112210010221100021
42301003321321210110101
53043323110220000032
641513405105423441
72364034661350033
oct261037171442421
947065483127307
1012167540000017
113971252139636
12144619863ab81
136a3517ab107c
14300caaa57c53
1516178b7e2097
hexb10f9e64511

12167540000017 has 2 divisors, whose sum is σ = 12167540000018. Its totient is φ = 12167540000016.

The previous prime is 12167539999999. The next prime is 12167540000053. The reversal of 12167540000017 is 71000004576121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12133211692176 + 34328307841 = 3483276^2 + 185279^2 .

It is an emirp because it is prime and its reverse (71000004576121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12167540000017 - 215 = 12167539967249 is a prime.

It is not a weakly prime, because it can be changed into another prime (12167540000087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6083770000008 + 6083770000009.

It is an arithmetic number, because the mean of its divisors is an integer number (6083770000009).

Almost surely, 212167540000017 is an apocalyptic number.

It is an amenable number.

12167540000017 is a deficient number, since it is larger than the sum of its proper divisors (1).

12167540000017 is an equidigital number, since it uses as much as digits as its factorization.

12167540000017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11760, while the sum is 34.

Adding to 12167540000017 its reverse (71000004576121), we get a palindrome (83167544576138).

The spelling of 12167540000017 in words is "twelve trillion, one hundred sixty-seven billion, five hundred forty million, seventeen", and thus it is an aban number.