Base | Representation |
---|---|
bin | 10110101010100110… |
… | …00011110110010111 |
3 | 1011102001010201212012 |
4 | 23111103003312113 |
5 | 144410112244403 |
6 | 5331244414435 |
7 | 610355233355 |
oct | 132523036627 |
9 | 34361121765 |
10 | 12168478103 |
11 | 5184874781 |
12 | 243724741b |
13 | 11bc033202 |
14 | 8361567d5 |
15 | 4b344eed8 |
hex | 2d54c3d97 |
12168478103 has 2 divisors, whose sum is σ = 12168478104. Its totient is φ = 12168478102.
The previous prime is 12168478087. The next prime is 12168478121. The reversal of 12168478103 is 30187486121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12168478103 - 24 = 12168478087 is a prime.
It is a super-3 number, since 3×121684781033 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12168478163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6084239051 + 6084239052.
It is an arithmetic number, because the mean of its divisors is an integer number (6084239052).
Almost surely, 212168478103 is an apocalyptic number.
12168478103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12168478103 is an equidigital number, since it uses as much as digits as its factorization.
12168478103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 41.
The spelling of 12168478103 in words is "twelve billion, one hundred sixty-eight million, four hundred seventy-eight thousand, one hundred three".
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