Base | Representation |
---|---|
bin | 10110101010100110… |
… | …01101010001111101 |
3 | 1011102001012200211221 |
4 | 23111103031101331 |
5 | 144410120013413 |
6 | 5331245313341 |
7 | 610355454112 |
oct | 132523152175 |
9 | 34361180757 |
10 | 12168516733 |
11 | 51848a07aa |
12 | 2437265851 |
13 | 11bc047979 |
14 | 836166909 |
15 | 4b345b68d |
hex | 2d54cd47d |
12168516733 has 2 divisors, whose sum is σ = 12168516734. Its totient is φ = 12168516732.
The previous prime is 12168516677. The next prime is 12168516739. The reversal of 12168516733 is 33761586121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6331862329 + 5836654404 = 79573^2 + 76398^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12168516733 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12168516733.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12168516739) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6084258366 + 6084258367.
It is an arithmetic number, because the mean of its divisors is an integer number (6084258367).
Almost surely, 212168516733 is an apocalyptic number.
It is an amenable number.
12168516733 is a deficient number, since it is larger than the sum of its proper divisors (1).
12168516733 is an equidigital number, since it uses as much as digits as its factorization.
12168516733 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 181440, while the sum is 43.
The spelling of 12168516733 in words is "twelve billion, one hundred sixty-eight million, five hundred sixteen thousand, seven hundred thirty-three".
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