Base | Representation |
---|---|
bin | 100100010001001… |
… | …1000000111110101 |
3 | 10010210221112201101 |
4 | 1020202120013311 |
5 | 4443021040003 |
6 | 320431530101 |
7 | 42105041101 |
oct | 11042300765 |
9 | 3123845641 |
10 | 1216971253 |
11 | 574a48573 |
12 | 29b689931 |
13 | 165187144 |
14 | b78aa901 |
15 | 71c8e11d |
hex | 488981f5 |
1216971253 has 2 divisors, whose sum is σ = 1216971254. Its totient is φ = 1216971252.
The previous prime is 1216971227. The next prime is 1216971257. The reversal of 1216971253 is 3521796121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1150091569 + 66879684 = 33913^2 + 8178^2 .
It is a cyclic number.
It is not a de Polignac number, because 1216971253 - 213 = 1216963061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1216971257) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 608485626 + 608485627.
It is an arithmetic number, because the mean of its divisors is an integer number (608485627).
Almost surely, 21216971253 is an apocalyptic number.
It is an amenable number.
1216971253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1216971253 is an equidigital number, since it uses as much as digits as its factorization.
1216971253 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 22680, while the sum is 37.
The square root of 1216971253 is about 34885.1150635912. The cubic root of 1216971253 is about 1067.6447607381.
The spelling of 1216971253 in words is "one billion, two hundred sixteen million, nine hundred seventy-one thousand, two hundred fifty-three".
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