Base | Representation |
---|---|
bin | 1011000101001010111100… |
… | …0000100011100111011110 |
3 | 1121010201122111211222120211 |
4 | 2301102233000203213132 |
5 | 3044103213113111032 |
6 | 41525001131403034 |
7 | 2365140403166203 |
oct | 261225700434736 |
9 | 47121574758524 |
10 | 12183463410142 |
11 | 3977a83522312 |
12 | 14492a12b347a |
13 | 6a4b84a2c13b |
14 | 30197b76dcaa |
15 | 161dbe709747 |
hex | b14af0239de |
12183463410142 has 8 divisors (see below), whose sum is σ = 18414700421832. Its totient is φ = 6045229936200.
The previous prime is 12183463410133. The next prime is 12183463410149. The reversal of 12183463410142 is 24101436438121.
12183463410142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 12183463410095 and 12183463410104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12183463410149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23250884109 + ... + 23250884632.
It is an arithmetic number, because the mean of its divisors is an integer number (2301837552729).
Almost surely, 212183463410142 is an apocalyptic number.
12183463410142 is a deficient number, since it is larger than the sum of its proper divisors (6231237011690).
12183463410142 is a wasteful number, since it uses less digits than its factorization.
12183463410142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46501768874.
The product of its (nonzero) digits is 110592, while the sum is 40.
Adding to 12183463410142 its reverse (24101436438121), we get a palindrome (36284899848263).
The spelling of 12183463410142 in words is "twelve trillion, one hundred eighty-three billion, four hundred sixty-three million, four hundred ten thousand, one hundred forty-two".
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