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12197057465903 is a prime number
BaseRepresentation
bin1011000101111101100101…
…0001110000111000101111
31121012000201220110120100112
42301133121101300320233
53044314033202402103
641535130103250235
72366131311564632
oct261373121607057
947160656416315
1012197057465903
113982819a65642
12144ba55a4997b
136a62401c7c0b
143024aad75c19
15162417da2cd8
hexb17d9470e2f

12197057465903 has 2 divisors, whose sum is σ = 12197057465904. Its totient is φ = 12197057465902.

The previous prime is 12197057465869. The next prime is 12197057465909. The reversal of 12197057465903 is 30956475079121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12197057465903 is a prime.

It is a super-2 number, since 2×121970574659032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12197057465909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6098528732951 + 6098528732952.

It is an arithmetic number, because the mean of its divisors is an integer number (6098528732952).

Almost surely, 212197057465903 is an apocalyptic number.

12197057465903 is a deficient number, since it is larger than the sum of its proper divisors (1).

12197057465903 is an equidigital number, since it uses as much as digits as its factorization.

12197057465903 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14288400, while the sum is 59.

The spelling of 12197057465903 in words is "twelve trillion, one hundred ninety-seven billion, fifty-seven million, four hundred sixty-five thousand, nine hundred three".