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1220001132013 is a prime number
BaseRepresentation
bin10001110000001101101…
…110111110110111101101
311022122000222100220001121
4101300031232332313231
5124442030242211023
62332243310140541
7154066523343166
oct21601556766755
94278028326047
101220001132013
11430443919664
1217853bab1751
138b07929a971
1443096a2676d
1521b05acbd5d
hex11c0dbbeded

1220001132013 has 2 divisors, whose sum is σ = 1220001132014. Its totient is φ = 1220001132012.

The previous prime is 1220001131981. The next prime is 1220001132047. The reversal of 1220001132013 is 3102311000221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1037908613284 + 182092518729 = 1018778^2 + 426723^2 .

It is a cyclic number.

It is not a de Polignac number, because 1220001132013 - 25 = 1220001131981 is a prime.

It is a super-2 number, since 2×12200011320132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1220001162013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610000566006 + 610000566007.

It is an arithmetic number, because the mean of its divisors is an integer number (610000566007).

Almost surely, 21220001132013 is an apocalyptic number.

It is an amenable number.

1220001132013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220001132013 is an equidigital number, since it uses as much as digits as its factorization.

1220001132013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1220001132013 its reverse (3102311000221), we get a palindrome (4322312132234).

The spelling of 1220001132013 in words is "one trillion, two hundred twenty billion, one million, one hundred thirty-two thousand, thirteen".