Base | Representation |
---|---|
bin | 1011000110001000111011… |
… | …1001000001110000001111 |
3 | 1121012022121020212121202211 |
4 | 2301202032321001300033 |
5 | 3044341303213402303 |
6 | 41540352310331251 |
7 | 2366266650441613 |
oct | 261421671016017 |
9 | 47168536777684 |
10 | 12200104434703 |
11 | 3984042996379 |
12 | 1450566359b27 |
13 | 6a6607545c33 |
14 | 3026b98c7343 |
15 | 16254562366d |
hex | b188ee41c0f |
12200104434703 has 2 divisors, whose sum is σ = 12200104434704. Its totient is φ = 12200104434702.
The previous prime is 12200104434673. The next prime is 12200104434709. The reversal of 12200104434703 is 30743440100221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12200104434703 - 217 = 12200104303631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12200104434709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100052217351 + 6100052217352.
It is an arithmetic number, because the mean of its divisors is an integer number (6100052217352).
Almost surely, 212200104434703 is an apocalyptic number.
12200104434703 is a deficient number, since it is larger than the sum of its proper divisors (1).
12200104434703 is an equidigital number, since it uses as much as digits as its factorization.
12200104434703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 12200104434703 its reverse (30743440100221), we get a palindrome (42943544534924).
The spelling of 12200104434703 in words is "twelve trillion, two hundred billion, one hundred four million, four hundred thirty-four thousand, seven hundred three".
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