Base | Representation |
---|---|
bin | 1011000110001000111101… |
… | …0110010110000100100111 |
3 | 1121012022121210100002011021 |
4 | 2301202033112112010213 |
5 | 3044341312200320403 |
6 | 41540353143152011 |
7 | 2366300102661205 |
oct | 261421726260447 |
9 | 47168553302137 |
10 | 12200112120103 |
11 | 3984047265546 |
12 | 1450568a45607 |
13 | 6a66090070cb |
14 | 3026ba928075 |
15 | 1625461408bd |
hex | b188f596127 |
12200112120103 has 2 divisors, whose sum is σ = 12200112120104. Its totient is φ = 12200112120102.
The previous prime is 12200112120083. The next prime is 12200112120139. The reversal of 12200112120103 is 30102121100221.
It is a weak prime.
It is an emirp because it is prime and its reverse (30102121100221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12200112120103 - 213 = 12200112111911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12200112120143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100056060051 + 6100056060052.
It is an arithmetic number, because the mean of its divisors is an integer number (6100056060052).
Almost surely, 212200112120103 is an apocalyptic number.
12200112120103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12200112120103 is an equidigital number, since it uses as much as digits as its factorization.
12200112120103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12200112120103 its reverse (30102121100221), we get a palindrome (42302233220324).
The spelling of 12200112120103 in words is "twelve trillion, two hundred billion, one hundred twelve million, one hundred twenty thousand, one hundred three".
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