Base | Representation |
---|---|
bin | 10001110000001110010… |
… | …101111100001000010011 |
3 | 11022122001200120201211021 |
4 | 101300032111330020103 |
5 | 124442040401010103 |
6 | 2332244313100311 |
7 | 154100006216005 |
oct | 21601625741023 |
9 | 4278050521737 |
10 | 1220011344403 |
11 | 430449664355 |
12 | 1785433b7697 |
13 | 8b07b4350b7 |
14 | 43098124375 |
15 | 21b06947bbd |
hex | 11c0e57c213 |
1220011344403 has 2 divisors, whose sum is σ = 1220011344404. Its totient is φ = 1220011344402.
The previous prime is 1220011344397. The next prime is 1220011344493. The reversal of 1220011344403 is 3044431100221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1220011344403 - 29 = 1220011343891 is a prime.
It is not a weakly prime, because it can be changed into another prime (1220011344493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610005672201 + 610005672202.
It is an arithmetic number, because the mean of its divisors is an integer number (610005672202).
Almost surely, 21220011344403 is an apocalyptic number.
1220011344403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220011344403 is an equidigital number, since it uses as much as digits as its factorization.
1220011344403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1220011344403 its reverse (3044431100221), we get a palindrome (4264442444624).
The spelling of 1220011344403 in words is "one trillion, two hundred twenty billion, eleven million, three hundred forty-four thousand, four hundred three".
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