Base | Representation |
---|---|
bin | 1011000110001000111111… |
… | …1001000010000100100111 |
3 | 1121012022122102110001120111 |
4 | 2301202033321002010213 |
5 | 3044341322012310343 |
6 | 41540354110113451 |
7 | 2366300243162566 |
oct | 261421771020447 |
9 | 47168572401514 |
10 | 12200121213223 |
11 | 3984051406319 |
12 | 145056baab887 |
13 | 6a660ab6bc58 |
14 | 3026bbc13bdd |
15 | 162546d39c9d |
hex | b188fe42127 |
12200121213223 has 2 divisors, whose sum is σ = 12200121213224. Its totient is φ = 12200121213222.
The previous prime is 12200121213139. The next prime is 12200121213253. The reversal of 12200121213223 is 32231212100221.
It is a strong prime.
It is an emirp because it is prime and its reverse (32231212100221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12200121213223 - 229 = 12199584342311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12200121213194 and 12200121213203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12200121213253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100060606611 + 6100060606612.
It is an arithmetic number, because the mean of its divisors is an integer number (6100060606612).
Almost surely, 212200121213223 is an apocalyptic number.
12200121213223 is a deficient number, since it is larger than the sum of its proper divisors (1).
12200121213223 is an equidigital number, since it uses as much as digits as its factorization.
12200121213223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 12200121213223 its reverse (32231212100221), we get a palindrome (44431333313444).
The spelling of 12200121213223 in words is "twelve trillion, two hundred billion, one hundred twenty-one million, two hundred thirteen thousand, two hundred twenty-three".
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