Base | Representation |
---|---|
bin | 10110101110011000… |
… | …11111100101001101 |
3 | 1011111021001000112201 |
4 | 23113030133211031 |
5 | 144441234423432 |
6 | 5334343001501 |
7 | 611222635111 |
oct | 132714374515 |
9 | 34437030481 |
10 | 12200311117 |
11 | 51a0837355 |
12 | 2445a39291 |
13 | 11c57ca607 |
14 | 83a481741 |
15 | 4b613bee7 |
hex | 2d731f94d |
12200311117 has 2 divisors, whose sum is σ = 12200311118. Its totient is φ = 12200311116.
The previous prime is 12200311073. The next prime is 12200311139. The reversal of 12200311117 is 71111300221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7664827401 + 4535483716 = 87549^2 + 67346^2 .
It is a cyclic number.
It is not a de Polignac number, because 12200311117 - 231 = 10052827469 is a prime.
It is a super-3 number, since 3×122003111173 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12200311094 and 12200311103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12200341117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100155558 + 6100155559.
It is an arithmetic number, because the mean of its divisors is an integer number (6100155559).
Almost surely, 212200311117 is an apocalyptic number.
It is an amenable number.
12200311117 is a deficient number, since it is larger than the sum of its proper divisors (1).
12200311117 is an equidigital number, since it uses as much as digits as its factorization.
12200311117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 12200311117 its reverse (71111300221), we get a palindrome (83311611338).
The spelling of 12200311117 in words is "twelve billion, two hundred million, three hundred eleven thousand, one hundred seventeen".
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