Base | Representation |
---|---|
bin | 1011000110001100101000… |
… | …1111010000111111000011 |
3 | 1121012102011122102200020011 |
4 | 2301203022033100333003 |
5 | 3044400323112320003 |
6 | 41541035155325351 |
7 | 2366333430562324 |
oct | 261431217207703 |
9 | 47172148380204 |
10 | 12201100120003 |
11 | 3984503a32493 |
12 | 14507a38b0857 |
13 | 6a6735902232 |
14 | 302771c3044b |
15 | 1625a2c5146d |
hex | b18ca3d0fc3 |
12201100120003 has 2 divisors, whose sum is σ = 12201100120004. Its totient is φ = 12201100120002.
The previous prime is 12201100119979. The next prime is 12201100120081. The reversal of 12201100120003 is 30002100110221.
12201100120003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12201100120003 - 29 = 12201100119491 is a prime.
It is not a weakly prime, because it can be changed into another prime (12201100120403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100550060001 + 6100550060002.
It is an arithmetic number, because the mean of its divisors is an integer number (6100550060002).
Almost surely, 212201100120003 is an apocalyptic number.
12201100120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201100120003 is an equidigital number, since it uses as much as digits as its factorization.
12201100120003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12201100120003 its reverse (30002100110221), we get a palindrome (42203200230224).
The spelling of 12201100120003 in words is "twelve trillion, two hundred one billion, one hundred million, one hundred twenty thousand, three".
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