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12201113100023 is a prime number
BaseRepresentation
bin1011000110001100101100…
…0000110001111011110111
31121012102012112212010110122
42301203023000301323313
53044400334423200043
641541040341442155
72366333646113051
oct261431300617367
947172175763418
1012201113100023
113984510298581
1214507a811035b
136a67384c8313
1430277384c8d1
151625a3e67368
hexb18cb031ef7

12201113100023 has 2 divisors, whose sum is σ = 12201113100024. Its totient is φ = 12201113100022.

The previous prime is 12201113099971. The next prime is 12201113100047. The reversal of 12201113100023 is 32000131110221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12201113100023 - 238 = 11926235193079 is a prime.

It is a super-2 number, since 2×122011131000232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12201113099974 and 12201113100010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12201113100623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100556550011 + 6100556550012.

It is an arithmetic number, because the mean of its divisors is an integer number (6100556550012).

Almost surely, 212201113100023 is an apocalyptic number.

12201113100023 is a deficient number, since it is larger than the sum of its proper divisors (1).

12201113100023 is an equidigital number, since it uses as much as digits as its factorization.

12201113100023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12201113100023 its reverse (32000131110221), we get a palindrome (44201244210244).

The spelling of 12201113100023 in words is "twelve trillion, two hundred one billion, one hundred thirteen million, one hundred thousand, twenty-three".