Base | Representation |
---|---|
bin | 10001110000010100010… |
… | …110010010101110000111 |
3 | 11022122022201011122211121 |
4 | 101300110112102232013 |
5 | 124442242144201411 |
6 | 2332302312414411 |
7 | 154102341506533 |
oct | 21602426225607 |
9 | 4278281148747 |
10 | 1220112100231 |
11 | 4304a0521732 |
12 | 1785710a7407 |
13 | 8b09628192b |
14 | 430a7670bc3 |
15 | 21b106eb571 |
hex | 11c14592b87 |
1220112100231 has 2 divisors, whose sum is σ = 1220112100232. Its totient is φ = 1220112100230.
The previous prime is 1220112100177. The next prime is 1220112100267. The reversal of 1220112100231 is 1320012110221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220112100231 - 213 = 1220112092039 is a prime.
It is a super-2 number, since 2×12201121002312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1220112100331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610056050115 + 610056050116.
It is an arithmetic number, because the mean of its divisors is an integer number (610056050116).
Almost surely, 21220112100231 is an apocalyptic number.
1220112100231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220112100231 is an equidigital number, since it uses as much as digits as its factorization.
1220112100231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1220112100231 its reverse (1320012110221), we get a palindrome (2540124210452).
The spelling of 1220112100231 in words is "one trillion, two hundred twenty billion, one hundred twelve million, one hundred thousand, two hundred thirty-one".
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