Base | Representation |
---|---|
bin | 10110101110011111… |
… | …11011100011010001 |
3 | 1011111022201210110221 |
4 | 23113033323203101 |
5 | 144442002241423 |
6 | 5334414153041 |
7 | 611233406656 |
oct | 132717734321 |
9 | 34438653427 |
10 | 12201212113 |
11 | 51a12a2282 |
12 | 24461b2781 |
13 | 11c5a5474c |
14 | 83a637c2d |
15 | 4b6268e5d |
hex | 2d73fb8d1 |
12201212113 has 2 divisors, whose sum is σ = 12201212114. Its totient is φ = 12201212112.
The previous prime is 12201212087. The next prime is 12201212129. The reversal of 12201212113 is 31121210221.
It is an a-pointer prime, because the next prime (12201212129) can be obtained adding 12201212113 to its sum of digits (16).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8547372304 + 3653839809 = 92452^2 + 60447^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12201212113 is a prime.
It is not a weakly prime, because it can be changed into another prime (12201212713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100606056 + 6100606057.
It is an arithmetic number, because the mean of its divisors is an integer number (6100606057).
Almost surely, 212201212113 is an apocalyptic number.
It is an amenable number.
12201212113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201212113 is an equidigital number, since it uses as much as digits as its factorization.
12201212113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12201212113 its reverse (31121210221), we get a palindrome (43322422334).
The spelling of 12201212113 in words is "twelve billion, two hundred one million, two hundred twelve thousand, one hundred thirteen".
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