Base | Representation |
---|---|
bin | 11011101111100000101001… |
… | …001100100101110011011111 |
3 | 121000000020121120111221022222 |
4 | 123233200221030211303133 |
5 | 111443021311230024244 |
6 | 1111255332312455555 |
7 | 34462041062012255 |
oct | 3357405114456337 |
9 | 530006546457288 |
10 | 122012122111199 |
11 | 3597106109a611 |
12 | 118269249aa5bb |
13 | 531090320b6b8 |
14 | 221b5bd8465d5 |
15 | e18c36974bee |
hex | 6ef829325cdf |
122012122111199 has 2 divisors, whose sum is σ = 122012122111200. Its totient is φ = 122012122111198.
The previous prime is 122012122111193. The next prime is 122012122111241. The reversal of 122012122111199 is 991111221210221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 122012122111199 - 232 = 122007827143903 is a prime.
It is a super-3 number, since 3×1220121221111993 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122012122111193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61006061055599 + 61006061055600.
It is an arithmetic number, because the mean of its divisors is an integer number (61006061055600).
Almost surely, 2122012122111199 is an apocalyptic number.
122012122111199 is a deficient number, since it is larger than the sum of its proper divisors (1).
122012122111199 is an equidigital number, since it uses as much as digits as its factorization.
122012122111199 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 35.
The spelling of 122012122111199 in words is "one hundred twenty-two trillion, twelve billion, one hundred twenty-two million, one hundred eleven thousand, one hundred ninety-nine".
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