Base | Representation |
---|---|
bin | 10001110000010100111… |
… | …100000101100110011011 |
3 | 11022122100101211000200122 |
4 | 101300110330011212123 |
5 | 124442302213223323 |
6 | 2332303305023455 |
7 | 154102521643205 |
oct | 21602474054633 |
9 | 4278311730618 |
10 | 1220122007963 |
11 | 4304a6079541 |
12 | 178574484b8b |
13 | 8b0983404b1 |
14 | 430a8acd775 |
15 | 21b11506ec8 |
hex | 11c14f0599b |
1220122007963 has 2 divisors, whose sum is σ = 1220122007964. Its totient is φ = 1220122007962.
The previous prime is 1220122007893. The next prime is 1220122007983. The reversal of 1220122007963 is 3697002210221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220122007963 - 222 = 1220117813659 is a prime.
It is a super-3 number, since 3×12201220079633 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1220122007983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610061003981 + 610061003982.
It is an arithmetic number, because the mean of its divisors is an integer number (610061003982).
Almost surely, 21220122007963 is an apocalyptic number.
1220122007963 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220122007963 is an equidigital number, since it uses as much as digits as its factorization.
1220122007963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 35.
The spelling of 1220122007963 in words is "one trillion, two hundred twenty billion, one hundred twenty-two million, seven thousand, nine hundred sixty-three".
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