Base | Representation |
---|---|
bin | 10001110000010101100… |
… | …111001101010111110101 |
3 | 11022122101012002022220021 |
4 | 101300111213031113311 |
5 | 124442313111440424 |
6 | 2332304351205141 |
7 | 154103020013434 |
oct | 21602547152765 |
9 | 4278335068807 |
10 | 1220133311989 |
11 | 43050149a409 |
12 | 1785782167b1 |
13 | 8b09a79a777 |
14 | 430aa3d311b |
15 | 21b124db4e4 |
hex | 11c159cd5f5 |
1220133311989 has 2 divisors, whose sum is σ = 1220133311990. Its totient is φ = 1220133311988.
The previous prime is 1220133311933. The next prime is 1220133312001. The reversal of 1220133311989 is 9891133310221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 901379348100 + 318753963889 = 949410^2 + 564583^2 .
It is an emirp because it is prime and its reverse (9891133310221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1220133311989 - 227 = 1219999094261 is a prime.
It is a super-2 number, since 2×12201333119892 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1220133381989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610066655994 + 610066655995.
It is an arithmetic number, because the mean of its divisors is an integer number (610066655995).
Almost surely, 21220133311989 is an apocalyptic number.
It is an amenable number.
1220133311989 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220133311989 is an equidigital number, since it uses as much as digits as its factorization.
1220133311989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 43.
The spelling of 1220133311989 in words is "one trillion, two hundred twenty billion, one hundred thirty-three million, three hundred eleven thousand, nine hundred eighty-nine".
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