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1220133311989 is a prime number
BaseRepresentation
bin10001110000010101100…
…111001101010111110101
311022122101012002022220021
4101300111213031113311
5124442313111440424
62332304351205141
7154103020013434
oct21602547152765
94278335068807
101220133311989
1143050149a409
121785782167b1
138b09a79a777
14430aa3d311b
1521b124db4e4
hex11c159cd5f5

1220133311989 has 2 divisors, whose sum is σ = 1220133311990. Its totient is φ = 1220133311988.

The previous prime is 1220133311933. The next prime is 1220133312001. The reversal of 1220133311989 is 9891133310221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 901379348100 + 318753963889 = 949410^2 + 564583^2 .

It is an emirp because it is prime and its reverse (9891133310221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1220133311989 - 227 = 1219999094261 is a prime.

It is a super-2 number, since 2×12201333119892 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1220133381989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610066655994 + 610066655995.

It is an arithmetic number, because the mean of its divisors is an integer number (610066655995).

Almost surely, 21220133311989 is an apocalyptic number.

It is an amenable number.

1220133311989 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220133311989 is an equidigital number, since it uses as much as digits as its factorization.

1220133311989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 43.

The spelling of 1220133311989 in words is "one trillion, two hundred twenty billion, one hundred thirty-three million, three hundred eleven thousand, nine hundred eighty-nine".