Base | Representation |
---|---|
bin | 11011101111100010110001… |
… | …101000001010101000011111 |
3 | 121000000110112002112122011022 |
4 | 123233202301220022220133 |
5 | 111443041003211310221 |
6 | 1111300351400314355 |
7 | 34462151564420015 |
oct | 3357426150125037 |
9 | 530013462478138 |
10 | 122014411041311 |
11 | 3597202613a698 |
12 | 118272634729bb |
13 | 5310ba94a9009 |
14 | 221b7598328b5 |
15 | e18d1c8ab4ab |
hex | 6ef8b1a0aa1f |
122014411041311 has 2 divisors, whose sum is σ = 122014411041312. Its totient is φ = 122014411041310.
The previous prime is 122014411041287. The next prime is 122014411041317. The reversal of 122014411041311 is 113140114410221.
It is a strong prime.
It is an emirp because it is prime and its reverse (113140114410221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122014411041311 - 26 = 122014411041247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122014411041317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61007205520655 + 61007205520656.
It is an arithmetic number, because the mean of its divisors is an integer number (61007205520656).
Almost surely, 2122014411041311 is an apocalyptic number.
122014411041311 is a deficient number, since it is larger than the sum of its proper divisors (1).
122014411041311 is an equidigital number, since it uses as much as digits as its factorization.
122014411041311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 26.
Adding to 122014411041311 its reverse (113140114410221), we get a palindrome (235154525451532).
The spelling of 122014411041311 in words is "one hundred twenty-two trillion, fourteen billion, four hundred eleven million, forty-one thousand, three hundred eleven".
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