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12202210101113 is a prime number
BaseRepresentation
bin1011000110010000110001…
…1001100000011101111001
31121012112001000001120001122
42301210030121200131321
53044410111241213423
641541341250155025
72366403066346004
oct261441431403571
947175030046048
1012202210101113
113984a2354474a
121450a53582a75
136a6881868ca6
1430283940a53b
1516261a4098c8
hexb190c660779

12202210101113 has 2 divisors, whose sum is σ = 12202210101114. Its totient is φ = 12202210101112.

The previous prime is 12202210101061. The next prime is 12202210101157. The reversal of 12202210101113 is 31110101220221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11858195006329 + 344015094784 = 3443573^2 + 586528^2 .

It is a cyclic number.

It is not a de Polignac number, because 12202210101113 - 222 = 12202205906809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12202210101091 and 12202210101100.

It is not a weakly prime, because it can be changed into another prime (12202210101163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101105050556 + 6101105050557.

It is an arithmetic number, because the mean of its divisors is an integer number (6101105050557).

Almost surely, 212202210101113 is an apocalyptic number.

It is an amenable number.

12202210101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12202210101113 is an equidigital number, since it uses as much as digits as its factorization.

12202210101113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 12202210101113 its reverse (31110101220221), we get a palindrome (43312311321334).

The spelling of 12202210101113 in words is "twelve trillion, two hundred two billion, two hundred ten million, one hundred one thousand, one hundred thirteen".