Base | Representation |
---|---|
bin | 1011000110010100000110… |
… | …0100001101111100110111 |
3 | 1121012121100011111212021201 |
4 | 2301211001210031330313 |
5 | 3044413423114220203 |
6 | 41542005552553331 |
7 | 2366434150255441 |
oct | 261450144157467 |
9 | 47177304455251 |
10 | 12203102101303 |
11 | 3985341002693 |
12 | 1451062252847 |
13 | 6a69945c1359 |
14 | 3028c1a83491 |
15 | 16266d8a5e1d |
hex | b194190df37 |
12203102101303 has 2 divisors, whose sum is σ = 12203102101304. Its totient is φ = 12203102101302.
The previous prime is 12203102101291. The next prime is 12203102101319. The reversal of 12203102101303 is 30310120130221.
12203102101303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12203102101303 - 213 = 12203102093111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12203102107303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101551050651 + 6101551050652.
It is an arithmetic number, because the mean of its divisors is an integer number (6101551050652).
Almost surely, 212203102101303 is an apocalyptic number.
12203102101303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12203102101303 is an equidigital number, since it uses as much as digits as its factorization.
12203102101303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12203102101303 its reverse (30310120130221), we get a palindrome (42513222231524).
The spelling of 12203102101303 in words is "twelve trillion, two hundred three billion, one hundred two million, one hundred one thousand, three hundred three".
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