Base | Representation |
---|---|
bin | 10001110000100000001… |
… | …101000101011110100001 |
3 | 11022122211120110111020121 |
4 | 101300200031011132201 |
5 | 124443144104411111 |
6 | 2332334140040241 |
7 | 154110305316133 |
oct | 21604015053641 |
9 | 4278746414217 |
10 | 1220311013281 |
11 | 430592831a88 |
12 | 178607833081 |
13 | 8b0c8548269 |
14 | 430c5c4d053 |
15 | 21b22ddd871 |
hex | 11c203457a1 |
1220311013281 has 2 divisors, whose sum is σ = 1220311013282. Its totient is φ = 1220311013280.
The previous prime is 1220311013221. The next prime is 1220311013287. The reversal of 1220311013281 is 1823101130221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1041818283025 + 178492730256 = 1020695^2 + 422484^2 .
It is a cyclic number.
It is not a de Polignac number, because 1220311013281 - 27 = 1220311013153 is a prime.
It is a super-2 number, since 2×12203110132812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1220311013287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610155506640 + 610155506641.
It is an arithmetic number, because the mean of its divisors is an integer number (610155506641).
Almost surely, 21220311013281 is an apocalyptic number.
It is an amenable number.
1220311013281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220311013281 is an equidigital number, since it uses as much as digits as its factorization.
1220311013281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
The spelling of 1220311013281 in words is "one trillion, two hundred twenty billion, three hundred eleven million, thirteen thousand, two hundred eighty-one".
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