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1220313324149 is a prime number
BaseRepresentation
bin10001110000100000010…
…101111001101001110101
311022122211201210220011022
4101300200111321221311
5124443200202333044
62332334301350525
7154110334052303
oct21604025715165
94278751726138
101220313324149
11430594070197
12178608568445
138b0c8b7703a
14430c6291273
1521b231e83ee
hex11c20579a75

1220313324149 has 2 divisors, whose sum is σ = 1220313324150. Its totient is φ = 1220313324148.

The previous prime is 1220313324073. The next prime is 1220313324169. The reversal of 1220313324149 is 9414233130221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1179000729124 + 41312595025 = 1085818^2 + 203255^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1220313324149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1220313324169) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610156662074 + 610156662075.

It is an arithmetic number, because the mean of its divisors is an integer number (610156662075).

Almost surely, 21220313324149 is an apocalyptic number.

It is an amenable number.

1220313324149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220313324149 is an equidigital number, since it uses as much as digits as its factorization.

1220313324149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 1220313324149 in words is "one trillion, two hundred twenty billion, three hundred thirteen million, three hundred twenty-four thousand, one hundred forty-nine".