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12203510014127 is a prime number
BaseRepresentation
bin1011000110010101100111…
…1000010010000010101111
31121012122101121001222111002
42301211121320102002233
53044420242030423002
641542114243550515
72366450232414605
oct261453170220257
947178347058432
1012203510014127
113985530292623
12145115698b43b
136a6a2ac734a3
1430291dd07875
151626945ce002
hexb1959e120af

12203510014127 has 2 divisors, whose sum is σ = 12203510014128. Its totient is φ = 12203510014126.

The previous prime is 12203510014093. The next prime is 12203510014159. The reversal of 12203510014127 is 72141001530221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12203510014127 - 212 = 12203510010031 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12203510014127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12203510011127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101755007063 + 6101755007064.

It is an arithmetic number, because the mean of its divisors is an integer number (6101755007064).

Almost surely, 212203510014127 is an apocalyptic number.

12203510014127 is a deficient number, since it is larger than the sum of its proper divisors (1).

12203510014127 is an equidigital number, since it uses as much as digits as its factorization.

12203510014127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3360, while the sum is 29.

Adding to 12203510014127 its reverse (72141001530221), we get a palindrome (84344511544348).

The spelling of 12203510014127 in words is "twelve trillion, two hundred three billion, five hundred ten million, fourteen thousand, one hundred twenty-seven".