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122043310013 is a prime number
BaseRepresentation
bin111000110101001011…
…0010001111110111101
3102200000102000111220002
41301222112101332331
53444421041410023
6132022123404045
711550230006312
oct1615226217675
9380012014802
10122043310013
11478382a3189
121b7a0083625
13b67c616a51
145c9a876d09
153294570b28
hex1c6a591fbd

122043310013 has 2 divisors, whose sum is σ = 122043310014. Its totient is φ = 122043310012.

The previous prime is 122043310001. The next prime is 122043310019. The reversal of 122043310013 is 310013340221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62761773529 + 59281536484 = 250523^2 + 243478^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122043310013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122043310019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61021655006 + 61021655007.

It is an arithmetic number, because the mean of its divisors is an integer number (61021655007).

Almost surely, 2122043310013 is an apocalyptic number.

It is an amenable number.

122043310013 is a deficient number, since it is larger than the sum of its proper divisors (1).

122043310013 is an equidigital number, since it uses as much as digits as its factorization.

122043310013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 122043310013 its reverse (310013340221), we get a palindrome (432056650234).

The spelling of 122043310013 in words is "one hundred twenty-two billion, forty-three million, three hundred ten thousand, thirteen".