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12210012002022 = 232941169191867
BaseRepresentation
bin1011000110101101110101…
…1011011001011011100110
31121020021011201201012002120
42301223131123121123212
53100022101033031042
641545111352050410
72400100323406542
oct261533533313346
947207151635076
1012210012002022
11398826750833a
121452470393a06
136a752603c0c3
14302d79668a22
15162925323dec
hexb1add6d96e6

12210012002022 has 16 divisors (see below), whose sum is σ = 24420854659392. Its totient is φ = 4069865558120.

The previous prime is 12210012001991. The next prime is 12210012002033. The reversal of 12210012002022 is 22020021001221.

It is a super-4 number, since 4×122100120020224 (a number of 53 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12210012001992 and 12210012002010.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34419468 + ... + 34772399.

It is an arithmetic number, because the mean of its divisors is an integer number (1526303416212).

Almost surely, 212210012002022 is an apocalyptic number.

12210012002022 is an abundant number, since it is smaller than the sum of its proper divisors (12210842657370).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12210012002022 is a wasteful number, since it uses less digits than its factorization.

12210012002022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69221283.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 12210012002022 its reverse (22020021001221), we get a palindrome (34230033003243).

The spelling of 12210012002022 in words is "twelve trillion, two hundred ten billion, twelve million, two thousand, twenty-two".

Divisors: 1 2 3 6 29411 58822 88233 176466 69191867 138383734 207575601 415151202 2035002000337 4070004000674 6105006001011 12210012002022