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12210211003117 is a prime number
BaseRepresentation
bin1011000110101110100101…
…0010100001101011101101
31121020021200121011111021111
42301223221102201223231
53100023003004044432
641545143221232021
72400105261033631
oct261535122415355
947207617144244
1012210211003117
113988359878856
121452506b62611
136a755833682a
14302d97c6adc1
15162937a32347
hexb1ae94a1aed

12210211003117 has 2 divisors, whose sum is σ = 12210211003118. Its totient is φ = 12210211003116.

The previous prime is 12210211003099. The next prime is 12210211003259. The reversal of 12210211003117 is 71130011201221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6253970630436 + 5956240372681 = 2500794^2 + 2440541^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12210211003117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12210211063117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105105501558 + 6105105501559.

It is an arithmetic number, because the mean of its divisors is an integer number (6105105501559).

Almost surely, 212210211003117 is an apocalyptic number.

It is an amenable number.

12210211003117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12210211003117 is an equidigital number, since it uses as much as digits as its factorization.

12210211003117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 22.

Adding to 12210211003117 its reverse (71130011201221), we get a palindrome (83340222204338).

The spelling of 12210211003117 in words is "twelve trillion, two hundred ten billion, two hundred eleven million, three thousand, one hundred seventeen".