Base | Representation |
---|---|
bin | 11011110000110100011101… |
… | …100110111101111001010011 |
3 | 121000022211220211012121201021 |
4 | 123300310131212331321103 |
5 | 112001010121213342433 |
6 | 1111404535051020311 |
7 | 34501405260364312 |
oct | 3360643546757123 |
9 | 530284824177637 |
10 | 122102122012243 |
11 | 359a624575331a |
12 | 1184026173a697 |
13 | 5319246cc7909 |
14 | 2221aba71a279 |
15 | e1b252cd222d |
hex | 6f0d1d9bde53 |
122102122012243 has 2 divisors, whose sum is σ = 122102122012244. Its totient is φ = 122102122012242.
The previous prime is 122102122012201. The next prime is 122102122012253. The reversal of 122102122012243 is 342210221201221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122102122012243 - 241 = 119903098756691 is a prime.
It is not a weakly prime, because it can be changed into another prime (122102122012253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61051061006121 + 61051061006122.
It is an arithmetic number, because the mean of its divisors is an integer number (61051061006122).
Almost surely, 2122102122012243 is an apocalyptic number.
122102122012243 is a deficient number, since it is larger than the sum of its proper divisors (1).
122102122012243 is an equidigital number, since it uses as much as digits as its factorization.
122102122012243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 122102122012243 its reverse (342210221201221), we get a palindrome (464312343213464).
The spelling of 122102122012243 in words is "one hundred twenty-two trillion, one hundred two billion, one hundred twenty-two million, twelve thousand, two hundred forty-three".
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