Base | Representation |
---|---|
bin | 1011000110110001100011… |
… | …1011101011011010011111 |
3 | 1121020100202022012222221122 |
4 | 2301230120323223122133 |
5 | 3100031122120220111 |
6 | 41545354413321155 |
7 | 2400134135103635 |
oct | 261543073533237 |
9 | 47210668188848 |
10 | 12211010320031 |
11 | 3988729a92446 |
12 | 14526aa7961bb |
13 | 6a7654b0a813 |
14 | 303032099355 |
15 | 162982cc1cdb |
hex | b1b18eeb69f |
12211010320031 has 2 divisors, whose sum is σ = 12211010320032. Its totient is φ = 12211010320030.
The previous prime is 12211010320027. The next prime is 12211010320037. The reversal of 12211010320031 is 13002301011221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12211010320031 - 22 = 12211010320027 is a prime.
It is a super-2 number, since 2×122110103200312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12211010319991 and 12211010320009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12211010320037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105505160015 + 6105505160016.
It is an arithmetic number, because the mean of its divisors is an integer number (6105505160016).
Almost surely, 212211010320031 is an apocalyptic number.
12211010320031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211010320031 is an equidigital number, since it uses as much as digits as its factorization.
12211010320031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12211010320031 its reverse (13002301011221), we get a palindrome (25213311331252).
The spelling of 12211010320031 in words is "twelve trillion, two hundred eleven billion, ten million, three hundred twenty thousand, thirty-one".
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