Base | Representation |
---|---|
bin | 10110101111101010… |
… | …11011010000010101 |
3 | 1011112000020011120221 |
4 | 23113311123100111 |
5 | 200002011310201 |
6 | 5335404554341 |
7 | 611413065334 |
oct | 132765332025 |
9 | 34460204527 |
10 | 12211041301 |
11 | 51a68a6078 |
12 | 24495529b1 |
13 | 11c7ab6634 |
14 | 83ba75d1b |
15 | 4b705b4a1 |
hex | 2d7d5b415 |
12211041301 has 2 divisors, whose sum is σ = 12211041302. Its totient is φ = 12211041300.
The previous prime is 12211041211. The next prime is 12211041313. The reversal of 12211041301 is 10314011221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7992538801 + 4218502500 = 89401^2 + 64950^2 .
It is a cyclic number.
It is not a de Polignac number, because 12211041301 - 215 = 12211008533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12211041331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105520650 + 6105520651.
It is an arithmetic number, because the mean of its divisors is an integer number (6105520651).
Almost surely, 212211041301 is an apocalyptic number.
It is an amenable number.
12211041301 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211041301 is an equidigital number, since it uses as much as digits as its factorization.
12211041301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12211041301 its reverse (10314011221), we get a palindrome (22525052522).
The spelling of 12211041301 in words is "twelve billion, two hundred eleven million, forty-one thousand, three hundred one".
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