Base | Representation |
---|---|
bin | 10110101111101011… |
… | …01010000000000111 |
3 | 1011112000100020110001 |
4 | 23113311222000013 |
5 | 200002020223303 |
6 | 5335410142131 |
7 | 611413436413 |
oct | 132765520007 |
9 | 34460306401 |
10 | 12211101703 |
11 | 51a6937499 |
12 | 2449581947 |
13 | 11c7b07c88 |
14 | 83ba8dd43 |
15 | 4b706e31d |
hex | 2d7d6a007 |
12211101703 has 2 divisors, whose sum is σ = 12211101704. Its totient is φ = 12211101702.
The previous prime is 12211101691. The next prime is 12211101713. The reversal of 12211101703 is 30710111221.
12211101703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12211101703 - 25 = 12211101671 is a prime.
It is a super-2 number, since 2×122111017032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12211101713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105550851 + 6105550852.
It is an arithmetic number, because the mean of its divisors is an integer number (6105550852).
Almost surely, 212211101703 is an apocalyptic number.
12211101703 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211101703 is an equidigital number, since it uses as much as digits as its factorization.
12211101703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 12211101703 its reverse (30710111221), we get a palindrome (42921212924).
The spelling of 12211101703 in words is "twelve billion, two hundred eleven million, one hundred one thousand, seven hundred three".
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