Base | Representation |
---|---|
bin | 1011000110110001111011… |
… | …1100001000001100001001 |
3 | 1121020101000022212012201021 |
4 | 2301230132330020030021 |
5 | 3100031323420214233 |
6 | 41545412413352441 |
7 | 2400136500531364 |
oct | 261543674101411 |
9 | 47211008765637 |
10 | 12211111101193 |
11 | 3988780967864 |
12 | 1452718498721 |
13 | 6a766c965a44 |
14 | 3030416110db |
15 | 16298ba7ce2d |
hex | b1b1ef08309 |
12211111101193 has 2 divisors, whose sum is σ = 12211111101194. Its totient is φ = 12211111101192.
The previous prime is 12211111101173. The next prime is 12211111101269. The reversal of 12211111101193 is 39110111111221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10930508801424 + 1280602299769 = 3306132^2 + 1131637^2 .
It is a cyclic number.
It is not a de Polignac number, because 12211111101193 - 29 = 12211111100681 is a prime.
It is a super-2 number, since 2×122111111011932 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12211111101173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105555550596 + 6105555550597.
It is an arithmetic number, because the mean of its divisors is an integer number (6105555550597).
Almost surely, 212211111101193 is an apocalyptic number.
It is an amenable number.
12211111101193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211111101193 is an equidigital number, since it uses as much as digits as its factorization.
12211111101193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 25.
The spelling of 12211111101193 in words is "twelve trillion, two hundred eleven billion, one hundred eleven million, one hundred one thousand, one hundred ninety-three".
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