Base | Representation |
---|---|
bin | 10001110001001111111… |
… | …100101001110110111111 |
3 | 11022201220101200110020002 |
4 | 101301033330221312333 |
5 | 130001314133342343 |
6 | 2332545432144515 |
7 | 154136202563045 |
oct | 21611774516677 |
9 | 4281811613202 |
10 | 1221112012223 |
11 | 430963995384 |
12 | 1787abb3813b |
13 | 8b1c548aa2c |
14 | 43160398395 |
15 | 21b6d3b18b8 |
hex | 11c4ff29dbf |
1221112012223 has 2 divisors, whose sum is σ = 1221112012224. Its totient is φ = 1221112012222.
The previous prime is 1221112012199. The next prime is 1221112012291. The reversal of 1221112012223 is 3222102111221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1221112012223 - 234 = 1203932143039 is a prime.
It is a super-2 number, since 2×12211120122232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1221112012195 and 1221112012204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221112012123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610556006111 + 610556006112.
It is an arithmetic number, because the mean of its divisors is an integer number (610556006112).
Almost surely, 21221112012223 is an apocalyptic number.
1221112012223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221112012223 is an equidigital number, since it uses as much as digits as its factorization.
1221112012223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1221112012223 its reverse (3222102111221), we get a palindrome (4443214123444).
The spelling of 1221112012223 in words is "one trillion, two hundred twenty-one billion, one hundred twelve million, twelve thousand, two hundred twenty-three".
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