Base | Representation |
---|---|
bin | 1011000110110001111110… |
… | …0101101101010011111111 |
3 | 1121020101001002100222122102 |
4 | 2301230133211231103333 |
5 | 3100031334213014101 |
6 | 41545413443135315 |
7 | 2400136662266603 |
oct | 261543745552377 |
9 | 47211032328572 |
10 | 12211122001151 |
11 | 3988787032097 |
12 | 145272007453b |
13 | 6a7671cb1118 |
14 | 303042c4b503 |
15 | 16298c9d286b |
hex | b1b1f96d4ff |
12211122001151 has 2 divisors, whose sum is σ = 12211122001152. Its totient is φ = 12211122001150.
The previous prime is 12211122001147. The next prime is 12211122001277. The reversal of 12211122001151 is 15110022111221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12211122001151 - 22 = 12211122001147 is a prime.
It is a super-2 number, since 2×122111220011512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12211122801151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105561000575 + 6105561000576.
It is an arithmetic number, because the mean of its divisors is an integer number (6105561000576).
Almost surely, 212211122001151 is an apocalyptic number.
12211122001151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211122001151 is an equidigital number, since it uses as much as digits as its factorization.
12211122001151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 12211122001151 its reverse (15110022111221), we get a palindrome (27321144112372).
The spelling of 12211122001151 in words is "twelve trillion, two hundred eleven billion, one hundred twenty-two million, one thousand, one hundred fifty-one".
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