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1221131003117 is a prime number
BaseRepresentation
bin10001110001010001000…
…101000110010011101101
311022201221201102021211112
4101301101011012103231
5130001334014044432
62332551351201405
7154136523160064
oct21612105062355
94281851367745
101221131003117
11430973686533
121787b6376265
138b1c93a9a4c
1443162add1db
1521b6edb37b2
hex11c511464ed

1221131003117 has 2 divisors, whose sum is σ = 1221131003118. Its totient is φ = 1221131003116.

The previous prime is 1221131003087. The next prime is 1221131003129. The reversal of 1221131003117 is 7113001311221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 870985426756 + 350145576361 = 933266^2 + 591731^2 .

It is a cyclic number.

It is not a de Polignac number, because 1221131003117 - 216 = 1221130937581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1221131003092 and 1221131003101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1221131003167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610565501558 + 610565501559.

It is an arithmetic number, because the mean of its divisors is an integer number (610565501559).

Almost surely, 21221131003117 is an apocalyptic number.

It is an amenable number.

1221131003117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221131003117 is an equidigital number, since it uses as much as digits as its factorization.

1221131003117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 1221131003117 its reverse (7113001311221), we get a palindrome (8334132314338).

The spelling of 1221131003117 in words is "one trillion, two hundred twenty-one billion, one hundred thirty-one million, three thousand, one hundred seventeen".