Base | Representation |
---|---|
bin | 11011110000111110101100… |
… | …000100010101111110101010 |
3 | 121000100220021001000102020011 |
4 | 123300332230010111332222 |
5 | 112001200113103343310 |
6 | 1111413552402322134 |
7 | 34502244335011342 |
oct | 3360765404257652 |
9 | 530326231012204 |
10 | 122113102012330 |
11 | 359aa96a670960 |
12 | 1184240695934a |
13 | 531a2a6a3bba0 |
14 | 222243caa1d22 |
15 | e1b696c2078a |
hex | 6f0fac115faa |
122113102012330 has 512 divisors, whose sum is σ = 277232981114880. Its totient is φ = 38068310016000.
The previous prime is 122113102012247. The next prime is 122113102012339. The reversal of 122113102012330 is 33210201311221.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is not an unprimeable number, because it can be changed into a prime (122113102012339) by changing a digit.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 184739942200 + ... + 184739942860.
It is an arithmetic number, because the mean of its divisors is an integer number (541470666240).
Almost surely, 2122113102012330 is an apocalyptic number.
122113102012330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
122113102012330 is an abundant number, since it is smaller than the sum of its proper divisors (155119879102550).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
122113102012330 is a wasteful number, since it uses less digits than its factorization.
122113102012330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1366.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 122113102012330 its reverse (33210201311221), we get a palindrome (155323303323551).
The spelling of 122113102012330 in words is "one hundred twenty-two trillion, one hundred thirteen billion, one hundred two million, twelve thousand, three hundred thirty".
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