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12211530040103 is a prime number
BaseRepresentation
bin1011000110110011011111…
…1010010000001100100111
31121020102002112011111212012
42301230313322100030213
53100033203142240403
641545522140544435
72400153045462542
oct261546772201447
947212075144765
1012211530040103
113988976398869
12145281485211b
136a77086a87a4
14303081105859
151629b3732ed8
hexb1b37e90327

12211530040103 has 2 divisors, whose sum is σ = 12211530040104. Its totient is φ = 12211530040102.

The previous prime is 12211530040051. The next prime is 12211530040139. The reversal of 12211530040103 is 30104003511221.

It is a strong prime.

It is an emirp because it is prime and its reverse (30104003511221) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12211530040103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12211530040153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105765020051 + 6105765020052.

It is an arithmetic number, because the mean of its divisors is an integer number (6105765020052).

Almost surely, 212211530040103 is an apocalyptic number.

12211530040103 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211530040103 is an equidigital number, since it uses as much as digits as its factorization.

12211530040103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 12211530040103 its reverse (30104003511221), we get a palindrome (42315533551324).

The spelling of 12211530040103 in words is "twelve trillion, two hundred eleven billion, five hundred thirty million, forty thousand, one hundred three".