Base | Representation |
---|---|
bin | 1011000110110101101000… |
… | …0000001110111110101011 |
3 | 1121020110120101110210001021 |
4 | 2301231122000032332223 |
5 | 3100040341110031243 |
6 | 41550055012433311 |
7 | 2400203162364343 |
oct | 261553200167653 |
9 | 47213511423037 |
10 | 12212102033323 |
11 | 398913a257835 |
12 | 1452954318837 |
13 | 6a779a04970a |
14 | 3030d707bd23 |
15 | 1629e8a6c6ed |
hex | b1b5a00efab |
12212102033323 has 2 divisors, whose sum is σ = 12212102033324. Its totient is φ = 12212102033322.
The previous prime is 12212102033311. The next prime is 12212102033399. The reversal of 12212102033323 is 32333020121221.
It is a weak prime.
It is an emirp because it is prime and its reverse (32333020121221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12212102033323 is a prime.
It is not a weakly prime, because it can be changed into another prime (12212102333323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106051016661 + 6106051016662.
It is an arithmetic number, because the mean of its divisors is an integer number (6106051016662).
Almost surely, 212212102033323 is an apocalyptic number.
12212102033323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212102033323 is an equidigital number, since it uses as much as digits as its factorization.
12212102033323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12212102033323 its reverse (32333020121221), we get a palindrome (44545122154544).
The spelling of 12212102033323 in words is "twelve trillion, two hundred twelve billion, one hundred two million, thirty-three thousand, three hundred twenty-three".
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