Base | Representation |
---|---|
bin | 1011000110110101101100… |
… | …1001011011001110010101 |
3 | 1121020110121201120120012112 |
4 | 2301231123021123032111 |
5 | 3100040411013014424 |
6 | 41550100540000405 |
7 | 2400203514435215 |
oct | 261553311331625 |
9 | 47213551516175 |
10 | 12212121219989 |
11 | 398914a071a89 |
12 | 145295a830105 |
13 | 6a77a1006882 |
14 | 3030d9834245 |
15 | 1629ea5ac60e |
hex | b1b5b25b395 |
12212121219989 has 2 divisors, whose sum is σ = 12212121219990. Its totient is φ = 12212121219988.
The previous prime is 12212121219943. The next prime is 12212121220021. The reversal of 12212121219989 is 98991212121221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11931380197489 + 280741022500 = 3454183^2 + 529850^2 .
It is a cyclic number.
It is not a de Polignac number, because 12212121219989 - 220 = 12212120171413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12212121219889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106060609994 + 6106060609995.
It is an arithmetic number, because the mean of its divisors is an integer number (6106060609995).
Almost surely, 212212121219989 is an apocalyptic number.
It is an amenable number.
12212121219989 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212121219989 is an equidigital number, since it uses as much as digits as its factorization.
12212121219989 is an evil number, because the sum of its binary digits is even.
The product of its digits is 186624, while the sum is 50.
The spelling of 12212121219989 in words is "twelve trillion, two hundred twelve billion, one hundred twenty-one million, two hundred nineteen thousand, nine hundred eighty-nine".
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