Base | Representation |
---|---|
bin | 1011000110110101101100… |
… | …1100011100010110000011 |
3 | 1121020110121210001202021122 |
4 | 2301231123030130112003 |
5 | 3100040411213323021 |
6 | 41550101004542455 |
7 | 2400203524241336 |
oct | 261553314342603 |
9 | 47213553052248 |
10 | 12212122011011 |
11 | 398914a56231a |
12 | 145295ab51a2b |
13 | 6a77a1222930 |
14 | 3030d999c61d |
15 | 1629ea6b6bab |
hex | b1b5b31c583 |
12212122011011 has 24 divisors (see below), whose sum is σ = 13456000716480. Its totient is φ = 11017519345152.
The previous prime is 12212122010983. The next prime is 12212122011043. The reversal of 12212122011011 is 11011022121221.
12212122011011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-12212122011011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12212122011071) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20351795 + ... + 20943251.
It is an arithmetic number, because the mean of its divisors is an integer number (560666696520).
Almost surely, 212212122011011 is an apocalyptic number.
12212122011011 is a deficient number, since it is larger than the sum of its proper divisors (1243878705469).
12212122011011 is an equidigital number, since it uses as much as digits as its factorization.
12212122011011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 592283 (or 592236 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 12212122011011 its reverse (11011022121221), we get a palindrome (23223144132232).
The spelling of 12212122011011 in words is "twelve trillion, two hundred twelve billion, one hundred twenty-two million, eleven thousand, eleven".
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