Base | Representation |
---|---|
bin | 10001110001010110011… |
… | …000101001010001011011 |
3 | 11022202011220220110122022 |
4 | 101301112120221101123 |
5 | 130002024310410042 |
6 | 2333004251045055 |
7 | 154141653560411 |
oct | 21612630512133 |
9 | 4282156813568 |
10 | 1221220013147 |
11 | 430a09951042 |
12 | 17882014078b |
13 | 8b2119731c4 |
14 | 4317086d2b1 |
15 | 21b77ae6cd2 |
hex | 11c5662945b |
1221220013147 has 2 divisors, whose sum is σ = 1221220013148. Its totient is φ = 1221220013146.
The previous prime is 1221220013099. The next prime is 1221220013177. The reversal of 1221220013147 is 7413100221221.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1221220013147 - 216 = 1221219947611 is a prime.
It is not a weakly prime, because it can be changed into another prime (1221220013177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610610006573 + 610610006574.
It is an arithmetic number, because the mean of its divisors is an integer number (610610006574).
Almost surely, 21221220013147 is an apocalyptic number.
1221220013147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221220013147 is an equidigital number, since it uses as much as digits as its factorization.
1221220013147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 1221220013147 its reverse (7413100221221), we get a palindrome (8634320234368).
The spelling of 1221220013147 in words is "one trillion, two hundred twenty-one billion, two hundred twenty million, thirteen thousand, one hundred forty-seven".
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