Base | Representation |
---|---|
bin | 1011000110110101111111… |
… | …1010001110010010111001 |
3 | 1121020110211021220221201111 |
4 | 2301231133322032102321 |
5 | 3100041041441332303 |
6 | 41550112512320321 |
7 | 2400205504536511 |
oct | 261553772162271 |
9 | 47213737827644 |
10 | 12212201120953 |
11 | 3989190185839 |
12 | 14529815430a1 |
13 | 6a77b4730b52 |
14 | 3031062b2841 |
15 | 162a025e1b6d |
hex | b1b5fe8e4b9 |
12212201120953 has 2 divisors, whose sum is σ = 12212201120954. Its totient is φ = 12212201120952.
The previous prime is 12212201120927. The next prime is 12212201120963. The reversal of 12212201120953 is 35902110221221.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6107684505129 + 6104516615824 = 2471373^2 + 2470732^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12212201120953 is a prime.
It is not a weakly prime, because it can be changed into another prime (12212201120963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106100560476 + 6106100560477.
It is an arithmetic number, because the mean of its divisors is an integer number (6106100560477).
Almost surely, 212212201120953 is an apocalyptic number.
It is an amenable number.
12212201120953 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212201120953 is an equidigital number, since it uses as much as digits as its factorization.
12212201120953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
The spelling of 12212201120953 in words is "twelve trillion, two hundred twelve billion, two hundred one million, one hundred twenty thousand, nine hundred fifty-three".
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