Base | Representation |
---|---|
bin | 11011110001001000001101… |
… | …110001001110101001001011 |
3 | 121000101212122220212002002112 |
4 | 123301020031301032221023 |
5 | 112001332040230301212 |
6 | 1111422403411252535 |
7 | 34503055663602122 |
oct | 3361101561165113 |
9 | 530355586762075 |
10 | 122123331103307 |
11 | 35a04239728356 |
12 | 118443a05aa14b |
13 | 531b24702a941 |
14 | 2222b2d41aab9 |
15 | e1ba94c82422 |
hex | 6f120dc4ea4b |
122123331103307 has 2 divisors, whose sum is σ = 122123331103308. Its totient is φ = 122123331103306.
The previous prime is 122123331103303. The next prime is 122123331103337. The reversal of 122123331103307 is 703301133321221.
It is a weak prime.
It is an emirp because it is prime and its reverse (703301133321221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122123331103307 - 22 = 122123331103303 is a prime.
It is not a weakly prime, because it can be changed into another prime (122123331103303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61061665551653 + 61061665551654.
It is an arithmetic number, because the mean of its divisors is an integer number (61061665551654).
Almost surely, 2122123331103307 is an apocalyptic number.
122123331103307 is a deficient number, since it is larger than the sum of its proper divisors (1).
122123331103307 is an equidigital number, since it uses as much as digits as its factorization.
122123331103307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13608, while the sum is 32.
Adding to 122123331103307 its reverse (703301133321221), we get a palindrome (825424464424528).
The spelling of 122123331103307 in words is "one hundred twenty-two trillion, one hundred twenty-three billion, three hundred thirty-one million, one hundred three thousand, three hundred seven".
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