Base | Representation |
---|---|
bin | 1011000110110110110001… |
… | …1111000011100110110101 |
3 | 1121020111100222220221210211 |
4 | 2301231230133003212311 |
5 | 3100042004444244333 |
6 | 41550145450345421 |
7 | 2400213646054006 |
oct | 261555437034665 |
9 | 47214328827724 |
10 | 12212412103093 |
11 | 3989289289844 |
12 | 1452a2012b271 |
13 | 6a7819361a57 |
14 | 3031263131ad |
15 | 162a15db9ecd |
hex | b1b6c7c39b5 |
12212412103093 has 2 divisors, whose sum is σ = 12212412103094. Its totient is φ = 12212412103092.
The previous prime is 12212412102929. The next prime is 12212412103097. The reversal of 12212412103093 is 39030121421221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10670041849009 + 1542370254084 = 3266503^2 + 1241922^2 .
It is a cyclic number.
It is not a de Polignac number, because 12212412103093 - 29 = 12212412102581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12212412103097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106206051546 + 6106206051547.
It is an arithmetic number, because the mean of its divisors is an integer number (6106206051547).
Almost surely, 212212412103093 is an apocalyptic number.
It is an amenable number.
12212412103093 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212412103093 is an equidigital number, since it uses as much as digits as its factorization.
12212412103093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 12212412103093 in words is "twelve trillion, two hundred twelve billion, four hundred twelve million, one hundred three thousand, ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •