Base | Representation |
---|---|
bin | 10110101111111001… |
… | …00101111011100001 |
3 | 1011112010202121201121 |
4 | 23113330211323201 |
5 | 200003001420113 |
6 | 5335513132241 |
7 | 611435051566 |
oct | 132774457341 |
9 | 34463677647 |
10 | 12212920033 |
11 | 51a7969646 |
12 | 244a0ba081 |
13 | 11c82c3802 |
14 | 83c00486d |
15 | 4b72cce8d |
hex | 2d7f25ee1 |
12212920033 has 2 divisors, whose sum is σ = 12212920034. Its totient is φ = 12212920032.
The previous prime is 12212919893. The next prime is 12212920039. The reversal of 12212920033 is 33002921221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6463034449 + 5749885584 = 80393^2 + 75828^2 .
It is an emirp because it is prime and its reverse (33002921221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12212920033 - 217 = 12212788961 is a prime.
It is not a weakly prime, because it can be changed into another prime (12212920039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106460016 + 6106460017.
It is an arithmetic number, because the mean of its divisors is an integer number (6106460017).
Almost surely, 212212920033 is an apocalyptic number.
It is an amenable number.
12212920033 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212920033 is an equidigital number, since it uses as much as digits as its factorization.
12212920033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
The spelling of 12212920033 in words is "twelve billion, two hundred twelve million, nine hundred twenty thousand, thirty-three".
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